Base | Representation |
---|---|
bin | 11100011101000110011111… |
… | …100111011010100110001101 |
3 | 121102002202110222102210000110 |
4 | 130131012133213122212031 |
5 | 112400334221320412303 |
6 | 1122054514511350233 |
7 | 35234303142540510 |
oct | 3435063747324615 |
9 | 542082428383013 |
10 | 125145140013453 |
11 | 3696983501300a |
12 | 12051b72222379 |
13 | 54aa19cc24cb1 |
14 | 22c90b2950d77 |
15 | e704a3e5a703 |
hex | 71d19f9da98d |
125145140013453 has 32 divisors (see below), whose sum is σ = 195534381837312. Its totient is φ = 69700943088000.
The previous prime is 125145140013451. The next prime is 125145140013493. The reversal of 125145140013453 is 354310041541521.
It is not a de Polignac number, because 125145140013453 - 21 = 125145140013451 is a prime.
It is a super-2 number, since 2×1251451400134532 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (125145140013451) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 68242851 + ... + 70052672.
It is an arithmetic number, because the mean of its divisors is an integer number (6110449432416).
Almost surely, 2125145140013453 is an apocalyptic number.
It is an amenable number.
125145140013453 is a deficient number, since it is larger than the sum of its proper divisors (70389241823859).
125145140013453 is a wasteful number, since it uses less digits than its factorization.
125145140013453 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 138296625.
The product of its (nonzero) digits is 144000, while the sum is 39.
Adding to 125145140013453 its reverse (354310041541521), we get a palindrome (479455181554974).
The spelling of 125145140013453 in words is "one hundred twenty-five trillion, one hundred forty-five billion, one hundred forty million, thirteen thousand, four hundred fifty-three".
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