Base | Representation |
---|---|
bin | 11100011101000110110111… |
… | …101010101011111111110111 |
3 | 121102002210112002201020220020 |
4 | 130131012313222223333313 |
5 | 112400341033120234333 |
6 | 1122055022524140223 |
7 | 35234316142404216 |
oct | 3435066752537767 |
9 | 542083462636806 |
10 | 125145543524343 |
11 | 36969a21866791 |
12 | 12052065397673 |
13 | 54aa2356c5634 |
14 | 22c911038b07d |
15 | e704c95b43b3 |
hex | 71d1b7aabff7 |
125145543524343 has 16 divisors (see below), whose sum is σ = 168836751874560. Its totient is φ = 82444959104256.
The previous prime is 125145543524311. The next prime is 125145543524371. The reversal of 125145543524343 is 343425345541521.
It is not a de Polignac number, because 125145543524343 - 25 = 125145543524311 is a prime.
It is a super-2 number, since 2×1251455435243432 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (125145543522343) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 326100655 + ... + 326484192.
It is an arithmetic number, because the mean of its divisors is an integer number (10552296992160).
Almost surely, 2125145543524343 is an apocalyptic number.
125145543524343 is a deficient number, since it is larger than the sum of its proper divisors (43691208350217).
125145543524343 is an equidigital number, since it uses as much as digits as its factorization.
125145543524343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 652585606.
The product of its digits is 17280000, while the sum is 51.
The spelling of 125145543524343 in words is "one hundred twenty-five trillion, one hundred forty-five billion, five hundred forty-three million, five hundred twenty-four thousand, three hundred forty-three".
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