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12520112105131 is a prime number
BaseRepresentation
bin1011011000110001000011…
…0101011010011010101011
31122022220121010202121121121
42312030100311122122223
53120112142144331011
642343354325320111
72431356022656031
oct266142065323253
948286533677547
1012520112105131
113a97827980594
1214a2594266037
136ca845506887
14313d95d4a551
1516aa24565e71
hexb6310d5a6ab

12520112105131 has 2 divisors, whose sum is σ = 12520112105132. Its totient is φ = 12520112105130.

The previous prime is 12520112105069. The next prime is 12520112105173. The reversal of 12520112105131 is 13150121102521.

12520112105131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12520112105131 - 27 = 12520112105003 is a prime.

It is a super-2 number, since 2×125201121051312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12520112105096 and 12520112105105.

It is not a weakly prime, because it can be changed into another prime (12520112105231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6260056052565 + 6260056052566.

It is an arithmetic number, because the mean of its divisors is an integer number (6260056052566).

Almost surely, 212520112105131 is an apocalyptic number.

12520112105131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12520112105131 is an equidigital number, since it uses as much as digits as its factorization.

12520112105131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 600, while the sum is 25.

Adding to 12520112105131 its reverse (13150121102521), we get a palindrome (25670233207652).

The spelling of 12520112105131 in words is "twelve trillion, five hundred twenty billion, one hundred twelve million, one hundred five thousand, one hundred thirty-one".