12521021402643 has 32 divisors (see below), whose sum is σ = 18028365653760. Its totient is φ = 7684048368000.

The previous prime is 12521021402641. The next prime is 12521021402717. The reversal of 12521021402643 is 34620412012521.

It is not a de Polignac number, because 12521021402643 - 2¹ = 12521021402641 is a prime.

It is a super-3 number, since 3×12521021402643³ (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (12521021402641) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 338213788 + ... + 338250806.

It is an arithmetic number, because the mean of its divisors is an integer number (563386426680).

Almost surely, 2^{12521021402643} is an apocalyptic number.

12521021402643 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

12521021402643 is a deficient number, since it is larger than the sum of its proper divisors (5507344251117).

12521021402643 is a wasteful number, since it uses less digits than its factorization.

12521021402643 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60659.

The product of its (nonzero) digits is 23040, while the sum is 33.

The spelling of 12521021402643 in words is "twelve trillion, five hundred twenty-one billion, twenty-one million, four hundred two thousand, six hundred forty-three".