Base | Representation |
---|---|
bin | 10111010100101001… |
… | …10010110010010001 |
3 | 1012022121221121110101 |
4 | 23222110302302101 |
5 | 201120420112113 |
6 | 5430245532401 |
7 | 622200621541 |
oct | 135224626221 |
9 | 35277847411 |
10 | 12521254033 |
11 | 5345a15532 |
12 | 2515414101 |
13 | 124714ba72 |
14 | 86ad47321 |
15 | 4d43d62dd |
hex | 2ea532c91 |
12521254033 has 2 divisors, whose sum is σ = 12521254034. Its totient is φ = 12521254032.
The previous prime is 12521254003. The next prime is 12521254079. The reversal of 12521254033 is 33045212521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7494018624 + 5027235409 = 86568^2 + 70903^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12521254033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12521253992 and 12521254010.
It is not a weakly prime, because it can be changed into another prime (12521254003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6260627016 + 6260627017.
It is an arithmetic number, because the mean of its divisors is an integer number (6260627017).
Almost surely, 212521254033 is an apocalyptic number.
It is an amenable number.
12521254033 is a deficient number, since it is larger than the sum of its proper divisors (1).
12521254033 is an equidigital number, since it uses as much as digits as its factorization.
12521254033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 12521254033 its reverse (33045212521), we get a palindrome (45566466554).
The spelling of 12521254033 in words is "twelve billion, five hundred twenty-one million, two hundred fifty-four thousand, thirty-three".
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