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125224154113 = 1091114779243
BaseRepresentation
bin111010010011111110…
…0001111010000000001
3102222020002100010200211
41310213330033100001
54022424340412423
6133305512114121
712022112514262
oct1644774172001
9388202303624
10125224154113
114911a852463
1220329395941
13ba68609416
1460bd0b6969
1533cd93810d
hex1d27f0f401

125224154113 has 4 divisors (see below), whose sum is σ = 125338934448. Its totient is φ = 125109373780.

The previous prime is 125224154057. The next prime is 125224154131. The reversal of 125224154113 is 311451422521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125224154113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (125224154213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57388531 + ... + 57390712.

It is an arithmetic number, because the mean of its divisors is an integer number (31334733612).

Almost surely, 2125224154113 is an apocalyptic number.

It is an amenable number.

125224154113 is a deficient number, since it is larger than the sum of its proper divisors (114780335).

125224154113 is a wasteful number, since it uses less digits than its factorization.

125224154113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 114780334.

The product of its digits is 9600, while the sum is 31.

Adding to 125224154113 its reverse (311451422521), we get a palindrome (436675576634).

The spelling of 125224154113 in words is "one hundred twenty-five billion, two hundred twenty-four million, one hundred fifty-four thousand, one hundred thirteen".

Divisors: 1 1091 114779243 125224154113