Base | Representation |
---|---|
bin | 11100011110010101101001… |
… | …101011011011000011011001 |
3 | 121102101212212101110000110002 |
4 | 130132111221223123003121 |
5 | 112403232303404041103 |
6 | 1122201532441102345 |
7 | 35243402321335061 |
oct | 3436255153330331 |
9 | 542355771400402 |
10 | 125230134440153 |
11 | 369a189016a866 |
12 | 120665327879b5 |
13 | 54b51c69b6982 |
14 | 22cd256b3a3a1 |
15 | e727cab2e488 |
hex | 71e569adb0d9 |
125230134440153 has 2 divisors, whose sum is σ = 125230134440154. Its totient is φ = 125230134440152.
The previous prime is 125230134440113. The next prime is 125230134440237. The reversal of 125230134440153 is 351044431032521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 116463637916224 + 8766496523929 = 10791832^2 + 2960827^2 .
It is a cyclic number.
It is not a de Polignac number, because 125230134440153 - 214 = 125230134423769 is a prime.
It is not a weakly prime, because it can be changed into another prime (125230134440113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62615067220076 + 62615067220077.
It is an arithmetic number, because the mean of its divisors is an integer number (62615067220077).
Almost surely, 2125230134440153 is an apocalyptic number.
It is an amenable number.
125230134440153 is a deficient number, since it is larger than the sum of its proper divisors (1).
125230134440153 is an equidigital number, since it uses as much as digits as its factorization.
125230134440153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 125230134440153 its reverse (351044431032521), we get a palindrome (476274565472674).
The spelling of 125230134440153 in words is "one hundred twenty-five trillion, two hundred thirty billion, one hundred thirty-four million, four hundred forty thousand, one hundred fifty-three".
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