Base | Representation |
---|---|
bin | 10010001110010011001… |
… | …001100101001010011001 |
3 | 11102201102020101002001120 |
4 | 102032103021211022121 |
5 | 131004204341323101 |
6 | 2355144534035453 |
7 | 156322160311266 |
oct | 22162311451231 |
9 | 4381366332046 |
10 | 1252304245401 |
11 | 44311010a890 |
12 | 1828561a8b89 |
13 | 91126858041 |
14 | 4487ccb026d |
15 | 228969deb36 |
hex | 12393265299 |
1252304245401 has 32 divisors (see below), whose sum is σ = 1827611501568. Its totient is φ = 756443759040.
The previous prime is 1252304245399. The next prime is 1252304245427. The reversal of 1252304245401 is 1045424032521.
It is not a de Polignac number, because 1252304245401 - 21 = 1252304245399 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1252304245471) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12598371 + ... + 12697383.
It is an arithmetic number, because the mean of its divisors is an integer number (57112859424).
Almost surely, 21252304245401 is an apocalyptic number.
1252304245401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1252304245401 is a deficient number, since it is larger than the sum of its proper divisors (575307256167).
1252304245401 is a wasteful number, since it uses less digits than its factorization.
1252304245401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100301.
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 1252304245401 its reverse (1045424032521), we get a palindrome (2297728277922).
The spelling of 1252304245401 in words is "one trillion, two hundred fifty-two billion, three hundred four million, two hundred forty-five thousand, four hundred one".
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