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1252344031241 is a prime number
BaseRepresentation
bin10010001110010101100…
…001010110100000001001
311102201112000020101222012
4102032111201112200021
5131004300032444431
62355152514505305
7156323152425062
oct22162541264011
94381460211865
101252344031241
11443130614546
12182867595235
1391131b78264
14448842a9569
152289a24d22b
hex12395856809

1252344031241 has 2 divisors, whose sum is σ = 1252344031242. Its totient is φ = 1252344031240.

The previous prime is 1252344031229. The next prime is 1252344031249. The reversal of 1252344031241 is 1421304432521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 853829592841 + 398514438400 = 924029^2 + 631280^2 .

It is an emirp because it is prime and its reverse (1421304432521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1252344031241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1252344031198 and 1252344031207.

It is not a weakly prime, because it can be changed into another prime (1252344031249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626172015620 + 626172015621.

It is an arithmetic number, because the mean of its divisors is an integer number (626172015621).

Almost surely, 21252344031241 is an apocalyptic number.

It is an amenable number.

1252344031241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1252344031241 is an equidigital number, since it uses as much as digits as its factorization.

1252344031241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 1252344031241 its reverse (1421304432521), we get a palindrome (2673648463762).

The spelling of 1252344031241 in words is "one trillion, two hundred fifty-two billion, three hundred forty-four million, thirty-one thousand, two hundred forty-one".