125241532433 has 4 divisors (see below), whose sum is σ = 125447861760. Its totient is φ = 125035203108.

The previous prime is 125241532417. The next prime is 125241532459. The reversal of 125241532433 is 334235142521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 125241532433 - 2⁴ = 125241532417 is a prime.

It is a super-4 number, since 4×125241532433⁴ (a number of 45 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 125241532393 and 125241532402.

It is not an unprimeable number, because it can be changed into a prime (125241532333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103163753 + ... + 103164966.

It is an arithmetic number, because the mean of its divisors is an integer number (31361965440).

Almost surely, 2^125241532433 is an apocalyptic number.

It is an amenable number.

125241532433 is a deficient number, since it is larger than the sum of its proper divisors (206329327).

125241532433 is an equidigital number, since it uses as much as digits as its factorization.

125241532433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 206329326.

The product of its digits is 86400, while the sum is 35.

Adding to 125241532433 its reverse (334235142521), we get a palindrome (459476674954).

The spelling of 125241532433 in words is "one hundred twenty-five billion, two hundred forty-one million, five hundred thirty-two thousand, four hundred thirty-three".