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1252435202153 is a prime number
BaseRepresentation
bin10010001110011010111…
…101001001000001101001
311102201202100210100221122
4102032122331021001221
5131004441402432103
62355205532545025
7156325340365352
oct22163275110151
94381670710848
101252435202153
11443178025603
12182892022175
1391147a1a145
144489243cd29
15228a325bb38
hex1239af49069

1252435202153 has 2 divisors, whose sum is σ = 1252435202154. Its totient is φ = 1252435202152.

The previous prime is 1252435202129. The next prime is 1252435202159. The reversal of 1252435202153 is 3512025342521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1070786204944 + 181648997209 = 1034788^2 + 426203^2 .

It is an emirp because it is prime and its reverse (3512025342521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1252435202153 - 220 = 1252434153577 is a prime.

It is not a weakly prime, because it can be changed into another prime (1252435202159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626217601076 + 626217601077.

It is an arithmetic number, because the mean of its divisors is an integer number (626217601077).

Almost surely, 21252435202153 is an apocalyptic number.

It is an amenable number.

1252435202153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1252435202153 is an equidigital number, since it uses as much as digits as its factorization.

1252435202153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72000, while the sum is 35.

The spelling of 1252435202153 in words is "one trillion, two hundred fifty-two billion, four hundred thirty-five million, two hundred two thousand, one hundred fifty-three".