Base | Representation |
---|---|
bin | 10010001110011011110… |
… | …111001000000001111111 |
3 | 11102201210102101121210220 |
4 | 102032123313020001333 |
5 | 131010004300334211 |
6 | 2355211234432423 |
7 | 156325613524134 |
oct | 22163367100177 |
9 | 4381712347726 |
10 | 1252450402431 |
11 | 443185667818 |
12 | 182897132713 |
13 | 9114ac0c9a7 |
14 | 4489447858b |
15 | 228a4760806 |
hex | 1239bdc807f |
1252450402431 has 16 divisors (see below), whose sum is σ = 1712342903040. Its totient is φ = 813802393280.
The previous prime is 1252450402403. The next prime is 1252450402439. The reversal of 1252450402431 is 1342040542521.
It is a cyclic number.
It is not a de Polignac number, because 1252450402431 - 26 = 1252450402367 is a prime.
It is a super-2 number, since 2×12524504024312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1252450402392 and 1252450402401.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1252450402439) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4870995 + ... + 5121668.
It is an arithmetic number, because the mean of its divisors is an integer number (107021431440).
Almost surely, 21252450402431 is an apocalyptic number.
1252450402431 is a deficient number, since it is larger than the sum of its proper divisors (459892500609).
1252450402431 is a wasteful number, since it uses less digits than its factorization.
1252450402431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9993726.
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 1252450402431 its reverse (1342040542521), we get a palindrome (2594490944952).
The spelling of 1252450402431 in words is "one trillion, two hundred fifty-two billion, four hundred fifty million, four hundred two thousand, four hundred thirty-one".
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