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12525202257 = 34175067419
BaseRepresentation
bin10111010101000111…
…10110101101010001
31012022220101012101220
423222203312231101
5201122422433012
65430510315253
7622246314441
oct135243665521
935286335356
1012525202257
115348171927
1225167b8b29
131247c01ba9
1486b694121
154d491608c
hex2ea8f6b51

12525202257 has 4 divisors (see below), whose sum is σ = 16700269680. Its totient is φ = 8350134836.

The previous prime is 12525202231. The next prime is 12525202267. The reversal of 12525202257 is 75220252521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12525202257 - 211 = 12525200209 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12525202267) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2087533707 + ... + 2087533712.

It is an arithmetic number, because the mean of its divisors is an integer number (4175067420).

Almost surely, 212525202257 is an apocalyptic number.

It is an amenable number.

12525202257 is a deficient number, since it is larger than the sum of its proper divisors (4175067423).

12525202257 is an equidigital number, since it uses as much as digits as its factorization.

12525202257 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4175067422.

The product of its (nonzero) digits is 28000, while the sum is 33.

Adding to 12525202257 its reverse (75220252521), we get a palindrome (87745454778).

The spelling of 12525202257 in words is "twelve billion, five hundred twenty-five million, two hundred two thousand, two hundred fifty-seven".

Divisors: 1 3 4175067419 12525202257