Base | Representation |
---|---|
bin | 10010001110100000110… |
… | …111101000101110000001 |
3 | 11102202000021111021112122 |
4 | 102032200313220232001 |
5 | 131010142303004101 |
6 | 2355223435334025 |
7 | 156330653632253 |
oct | 22164067505601 |
9 | 4382007437478 |
10 | 1252534422401 |
11 | 443219034209 |
12 | 1828bb2b1315 |
13 | 91162449a52 |
14 | 448a16a9cd3 |
15 | 228abd0a51b |
hex | 123a0de8b81 |
1252534422401 has 2 divisors, whose sum is σ = 1252534422402. Its totient is φ = 1252534422400.
The previous prime is 1252534422397. The next prime is 1252534422427. The reversal of 1252534422401 is 1042244352521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1108135182400 + 144399240001 = 1052680^2 + 379999^2 .
It is a cyclic number.
It is not a de Polignac number, because 1252534422401 - 22 = 1252534422397 is a prime.
It is not a weakly prime, because it can be changed into another prime (1252534422481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626267211200 + 626267211201.
It is an arithmetic number, because the mean of its divisors is an integer number (626267211201).
Almost surely, 21252534422401 is an apocalyptic number.
It is an amenable number.
1252534422401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1252534422401 is an equidigital number, since it uses as much as digits as its factorization.
1252534422401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76800, while the sum is 35.
Adding to 1252534422401 its reverse (1042244352521), we get a palindrome (2294778774922).
The spelling of 1252534422401 in words is "one trillion, two hundred fifty-two billion, five hundred thirty-four million, four hundred twenty-two thousand, four hundred one".
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