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125254089953 is a prime number
BaseRepresentation
bin111010010100110111…
…0011011110011100001
3102222022011200000221122
41310221232123303201
54023010021334303
6133312501502025
712022625124626
oct1645156336341
9388264600848
10125254089953
1149135739723
1220337411915
13ba7188b135
1460c306a34d
1533d139ce38
hex1d29b9bce1

125254089953 has 2 divisors, whose sum is σ = 125254089954. Its totient is φ = 125254089952.

The previous prime is 125254089949. The next prime is 125254089973. The reversal of 125254089953 is 359980452521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71959135504 + 53294954449 = 268252^2 + 230857^2 .

It is a cyclic number.

It is not a de Polignac number, because 125254089953 - 22 = 125254089949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 125254089895 and 125254089904.

It is not a weakly prime, because it can be changed into another prime (125254089973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62627044976 + 62627044977.

It is an arithmetic number, because the mean of its divisors is an integer number (62627044977).

Almost surely, 2125254089953 is an apocalyptic number.

It is an amenable number.

125254089953 is a deficient number, since it is larger than the sum of its proper divisors (1).

125254089953 is an equidigital number, since it uses as much as digits as its factorization.

125254089953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888000, while the sum is 53.

The spelling of 125254089953 in words is "one hundred twenty-five billion, two hundred fifty-four million, eighty-nine thousand, nine hundred fifty-three".