Base | Representation |
---|---|
bin | 10111010101001001… |
… | …10001100001000001 |
3 | 1012022220211102211101 |
4 | 23222210301201001 |
5 | 201123003140022 |
6 | 5430515414401 |
7 | 622251336634 |
oct | 135244614101 |
9 | 35286742741 |
10 | 12525443137 |
11 | 53483168a9 |
12 | 25168b4401 |
13 | 1247c8771c |
14 | 86b717c1b |
15 | 4d4962627 |
hex | 2ea931841 |
12525443137 has 2 divisors, whose sum is σ = 12525443138. Its totient is φ = 12525443136.
The previous prime is 12525443111. The next prime is 12525443153. The reversal of 12525443137 is 73134452521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9058470976 + 3466972161 = 95176^2 + 58881^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12525443137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12525443096 and 12525443105.
It is not a weakly prime, because it can be changed into another prime (12525443237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6262721568 + 6262721569.
It is an arithmetic number, because the mean of its divisors is an integer number (6262721569).
Almost surely, 212525443137 is an apocalyptic number.
It is an amenable number.
12525443137 is a deficient number, since it is larger than the sum of its proper divisors (1).
12525443137 is an equidigital number, since it uses as much as digits as its factorization.
12525443137 is an evil number, because the sum of its binary digits is even.
The product of its digits is 100800, while the sum is 37.
Adding to 12525443137 its reverse (73134452521), we get a palindrome (85659895658).
The spelling of 12525443137 in words is "twelve billion, five hundred twenty-five million, four hundred forty-three thousand, one hundred thirty-seven".
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