Base | Representation |
---|---|
bin | 111010010100111011… |
… | …0001011101011001011 |
3 | 102222022022111020001220 |
4 | 1310221312023223023 |
5 | 4023011031333120 |
6 | 133313013213123 |
7 | 12022651314303 |
oct | 1645166135313 |
9 | 388268436056 |
10 | 125256121035 |
11 | 491368a6701 |
12 | 203380311a3 |
13 | ba7211c766 |
14 | 60c3438603 |
15 | 33d164eb40 |
hex | 1d29d8bacb |
125256121035 has 32 divisors (see below), whose sum is σ = 202898961408. Its totient is φ = 65977027200.
The previous prime is 125256121027. The next prime is 125256121043. The reversal of 125256121035 is 530121652521.
It is an interprime number because it is at equal distance from previous prime (125256121027) and next prime (125256121043).
It is not a de Polignac number, because 125256121035 - 23 = 125256121027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 125256120987 and 125256121005.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 467610 + ... + 684960.
It is an arithmetic number, because the mean of its divisors is an integer number (6340592544).
Almost surely, 2125256121035 is an apocalyptic number.
125256121035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
125256121035 is a deficient number, since it is larger than the sum of its proper divisors (77642840373).
125256121035 is a wasteful number, since it uses less digits than its factorization.
125256121035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 217835.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 125256121035 its reverse (530121652521), we get a palindrome (655377773556).
The spelling of 125256121035 in words is "one hundred twenty-five billion, two hundred fifty-six million, one hundred twenty-one thousand, thirty-five".
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