Base | Representation |
---|---|
bin | 10111010101001011… |
… | …11010011101011001 |
3 | 1012022221101121200011 |
4 | 23222211322131121 |
5 | 201123042220123 |
6 | 5430530041521 |
7 | 622254022666 |
oct | 135245723531 |
9 | 35287347604 |
10 | 12525741913 |
11 | 5348500323 |
12 | 2516a192a1 |
13 | 1248060709 |
14 | 86b794a6d |
15 | 4d49c0e0d |
hex | 2ea97a759 |
12525741913 has 2 divisors, whose sum is σ = 12525741914. Its totient is φ = 12525741912.
The previous prime is 12525741869. The next prime is 12525741923. The reversal of 12525741913 is 31914752521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10504610064 + 2021131849 = 102492^2 + 44957^2 .
It is a cyclic number.
It is not a de Polignac number, because 12525741913 - 217 = 12525610841 is a prime.
It is a super-3 number, since 3×125257419133 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (12525741923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6262870956 + 6262870957.
It is an arithmetic number, because the mean of its divisors is an integer number (6262870957).
Almost surely, 212525741913 is an apocalyptic number.
It is an amenable number.
12525741913 is a deficient number, since it is larger than the sum of its proper divisors (1).
12525741913 is an equidigital number, since it uses as much as digits as its factorization.
12525741913 is an evil number, because the sum of its binary digits is even.
The product of its digits is 75600, while the sum is 40.
The spelling of 12525741913 in words is "twelve billion, five hundred twenty-five million, seven hundred forty-one thousand, nine hundred thirteen".
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