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125300530311134 = 21072213326454457
BaseRepresentation
bin11100011111010111001101…
…100110010110111111011110
3121102122121120101200210012212
4130133113031212112333132
5112410410441224424014
61122254134033000422
735251443643351403
oct3437271546267736
9542577511623185
10125300530311134
1136a19724867632
12120780ba0b3112
1354bba351583b9
1422d28141602aa
15e7454ad8a23e
hex71f5cd996fde

125300530311134 has 16 divisors (see below), whose sum is σ = 189715923372528. Its totient is φ = 62061942140352.

The previous prime is 125300530311109. The next prime is 125300530311167. The reversal of 125300530311134 is 431113035003521.

It is a self number, because there is not a number n which added to its sum of digits gives 125300530311134.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8490767 + ... + 17963690.

It is an arithmetic number, because the mean of its divisors is an integer number (11857245210783).

Almost surely, 2125300530311134 is an apocalyptic number.

125300530311134 is a deficient number, since it is larger than the sum of its proper divisors (64415393061394).

125300530311134 is a wasteful number, since it uses less digits than its factorization.

125300530311134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26476699.

The product of its (nonzero) digits is 16200, while the sum is 32.

Adding to 125300530311134 its reverse (431113035003521), we get a palindrome (556413565314655).

The spelling of 125300530311134 in words is "one hundred twenty-five trillion, three hundred billion, five hundred thirty million, three hundred eleven thousand, one hundred thirty-four".

Divisors: 1 2 107 214 22133 44266 2368231 4736462 26454457 52908914 2830626899 5661253798 585516496781 1171032993562 62650265155567 125300530311134