1253040153 has 4 divisors (see below), whose sum is σ = 1670720208. Its totient is φ = 835360100.

The previous prime is 1253040121. The next prime is 1253040157. The reversal of 1253040153 is 3510403521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3510403521 = 3 ⋅1170134507.

It is a cyclic number.

It is not a de Polignac number, because 1253040153 - 2⁵ = 1253040121 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1253040157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 208840023 + ... + 208840028.

It is an arithmetic number, because the mean of its divisors is an integer number (417680052).

Almost surely, 2^1253040153 is an apocalyptic number.

It is an amenable number.

1253040153 is a deficient number, since it is larger than the sum of its proper divisors (417680055).

1253040153 is an equidigital number, since it uses as much as digits as its factorization.

1253040153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 417680054.

The product of its (nonzero) digits is 1800, while the sum is 24.

The square root of 1253040153 is about 35398.3072052888. The cubic root of 1253040153 is about 1078.0899461184.

Adding to 1253040153 its reverse (3510403521), we get a palindrome (4763443674).

The spelling of 1253040153 in words is "one billion, two hundred fifty-three million, forty thousand, one hundred fifty-three".