Base | Representation |
---|---|
bin | 1011011001011011001100… |
… | …0101010010110110011011 |
3 | 1122100222210111022002211222 |
4 | 2312112303011102312123 |
5 | 3120303324033041102 |
6 | 42352505021042255 |
7 | 2432236241310002 |
oct | 266266305226633 |
9 | 48328714262758 |
10 | 12531424112027 |
11 | 3aa1602243817 |
12 | 14a48106b638b |
13 | 6cb928c74192 |
14 | 31474a437c39 |
15 | 16ae876d6aa2 |
hex | b65b3152d9b |
12531424112027 has 2 divisors, whose sum is σ = 12531424112028. Its totient is φ = 12531424112026.
The previous prime is 12531424111993. The next prime is 12531424112033. The reversal of 12531424112027 is 72021142413521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12531424112027 - 242 = 8133377600923 is a prime.
It is not a weakly prime, because it can be changed into another prime (12531424112527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6265712056013 + 6265712056014.
It is an arithmetic number, because the mean of its divisors is an integer number (6265712056014).
Almost surely, 212531424112027 is an apocalyptic number.
12531424112027 is a deficient number, since it is larger than the sum of its proper divisors (1).
12531424112027 is an equidigital number, since it uses as much as digits as its factorization.
12531424112027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 35.
Adding to 12531424112027 its reverse (72021142413521), we get a palindrome (84552566525548).
The spelling of 12531424112027 in words is "twelve trillion, five hundred thirty-one billion, four hundred twenty-four million, one hundred twelve thousand, twenty-seven".
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