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12532465131 = 34177488377
BaseRepresentation
bin10111010101111111…
…00011110111101011
31012100102001012012020
423222333203313223
5201131302341011
65431330115523
7622365124134
oct135277436753
935312035166
1012532465131
1153512825aa
12251911bba3
131249575954
1486c624c8b
154d539d006
hex2eafe3deb

12532465131 has 4 divisors (see below), whose sum is σ = 16709953512. Its totient is φ = 8354976752.

The previous prime is 12532465109. The next prime is 12532465133. The reversal of 12532465131 is 13156423521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12532465131 - 222 = 12528270827 is a prime.

It is a super-2 number, since 2×125324651312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12532465092 and 12532465101.

It is not an unprimeable number, because it can be changed into a prime (12532465133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2088744186 + ... + 2088744191.

It is an arithmetic number, because the mean of its divisors is an integer number (4177488378).

Almost surely, 212532465131 is an apocalyptic number.

12532465131 is a deficient number, since it is larger than the sum of its proper divisors (4177488381).

12532465131 is an equidigital number, since it uses as much as digits as its factorization.

12532465131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4177488380.

The product of its digits is 21600, while the sum is 33.

Adding to 12532465131 its reverse (13156423521), we get a palindrome (25688888652).

The spelling of 12532465131 in words is "twelve billion, five hundred thirty-two million, four hundred sixty-five thousand, one hundred thirty-one".

Divisors: 1 3 4177488377 12532465131