Base | Representation |
---|---|
bin | 10010001111001101110… |
… | …111000100010101010011 |
3 | 11102210221212211101201101 |
4 | 102033031313010111103 |
5 | 131013214021414313 |
6 | 2355430402045231 |
7 | 156355450560235 |
oct | 22171567042523 |
9 | 4383855741641 |
10 | 1253289248083 |
11 | 44357611a994 |
12 | 182a90049817 |
13 | 91252943b72 |
14 | 44933a36255 |
15 | 2290320c5dd |
hex | 123cddc4553 |
1253289248083 has 2 divisors, whose sum is σ = 1253289248084. Its totient is φ = 1253289248082.
The previous prime is 1253289248053. The next prime is 1253289248087. The reversal of 1253289248083 is 3808429823521.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1253289248083 is a prime.
It is not a weakly prime, because it can be changed into another prime (1253289248087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626644624041 + 626644624042.
It is an arithmetic number, because the mean of its divisors is an integer number (626644624042).
Almost surely, 21253289248083 is an apocalyptic number.
1253289248083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1253289248083 is an equidigital number, since it uses as much as digits as its factorization.
1253289248083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6635520, while the sum is 55.
The spelling of 1253289248083 in words is "one trillion, two hundred fifty-three billion, two hundred eighty-nine million, two hundred forty-eight thousand, eighty-three".
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