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1253354454041 is a prime number
BaseRepresentation
bin10010001111010001101…
…111110011110000011001
311102211010102112012110212
4102033101233303300121
5131013332220012131
62355441051420505
7156360202036124
oct22172157636031
94384112465425
101253354454041
114435a9a07108
12182aa9a54735
13912632c4581
144493c56b3bb
1522908cdca2b
hex123d1bf3c19

1253354454041 has 2 divisors, whose sum is σ = 1253354454042. Its totient is φ = 1253354454040.

The previous prime is 1253354454017. The next prime is 1253354454067. The reversal of 1253354454041 is 1404544533521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1251928258816 + 1426195225 = 1118896^2 + 37765^2 .

It is a cyclic number.

It is not a de Polignac number, because 1253354454041 - 218 = 1253354191897 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1253354454041.

It is not a weakly prime, because it can be changed into another prime (1253354457041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626677227020 + 626677227021.

It is an arithmetic number, because the mean of its divisors is an integer number (626677227021).

Almost surely, 21253354454041 is an apocalyptic number.

It is an amenable number.

1253354454041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1253354454041 is an equidigital number, since it uses as much as digits as its factorization.

1253354454041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576000, while the sum is 41.

Adding to 1253354454041 its reverse (1404544533521), we get a palindrome (2657898987562).

The spelling of 1253354454041 in words is "one trillion, two hundred fifty-three billion, three hundred fifty-four million, four hundred fifty-four thousand, forty-one".