12534010523051 has 4 divisors (see below), whose sum is σ = 12534116146104. Its totient is φ = 12533904900000.

The previous prime is 12534010523039. The next prime is 12534010523077. The reversal of 12534010523051 is 15032501043521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12534010523051 - 2⁴² = 8135964011947 is a prime.

It is a super-3 number, since 3×12534010523051³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12534010522999 and 12534010523017.

It is not an unprimeable number, because it can be changed into a prime (12534010523081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52633325 + ... + 52870926.

It is an arithmetic number, because the mean of its divisors is an integer number (3133529036526).

Almost surely, 2^{12534010523051} is an apocalyptic number.

12534010523051 is a deficient number, since it is larger than the sum of its proper divisors (105623053).

12534010523051 is a wasteful number, since it uses less digits than its factorization.

12534010523051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105623052.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 12534010523051 its reverse (15032501043521), we get a palindrome (27566511566572).

The spelling of 12534010523051 in words is "twelve trillion, five hundred thirty-four billion, ten million, five hundred twenty-three thousand, fifty-one".