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125342703433 is a prime number
BaseRepresentation
bin111010010111100000…
…0011101111101001001
3102222112100102001210101
41310233000131331021
54023200213002213
6133325345045401
712025052254153
oct1645700357511
9388470361711
10125342703433
1149180763302
1220361026861
13ba87045c4c
1460d0b35ad3
1533d9053bdd
hex1d2f01df49

125342703433 has 2 divisors, whose sum is σ = 125342703434. Its totient is φ = 125342703432.

The previous prime is 125342703427. The next prime is 125342703491. The reversal of 125342703433 is 334307243521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125324496144 + 18207289 = 354012^2 + 4267^2 .

It is a cyclic number.

It is not a de Polignac number, because 125342703433 - 213 = 125342695241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 125342703392 and 125342703401.

It is not a weakly prime, because it can be changed into another prime (125342763433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62671351716 + 62671351717.

It is an arithmetic number, because the mean of its divisors is an integer number (62671351717).

Almost surely, 2125342703433 is an apocalyptic number.

It is an amenable number.

125342703433 is a deficient number, since it is larger than the sum of its proper divisors (1).

125342703433 is an equidigital number, since it uses as much as digits as its factorization.

125342703433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 181440, while the sum is 37.

Adding to 125342703433 its reverse (334307243521), we get a palindrome (459649946954).

The spelling of 125342703433 in words is "one hundred twenty-five billion, three hundred forty-two million, seven hundred three thousand, four hundred thirty-three".