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125344433 is a prime number
BaseRepresentation
bin1110111100010…
…01101010110001
322201212011020102
413132021222301
5224042010213
620234322145
73051260444
oct736115261
9281764212
10125344433
1164832145
1235b89355
131cc78706
141290b65b
15b00e158
hex7789ab1

125344433 has 2 divisors, whose sum is σ = 125344434. Its totient is φ = 125344432.

The previous prime is 125344403. The next prime is 125344469. The reversal of 125344433 is 334443521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 91623184 + 33721249 = 9572^2 + 5807^2 .

It is a cyclic number.

It is not a de Polignac number, because 125344433 - 26 = 125344369 is a prime.

It is a super-2 number, since 2×1253444332 = 31422453768182978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 125344396 and 125344405.

It is not a weakly prime, because it can be changed into another prime (125344403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62672216 + 62672217.

It is an arithmetic number, because the mean of its divisors is an integer number (62672217).

Almost surely, 2125344433 is an apocalyptic number.

It is an amenable number.

125344433 is a deficient number, since it is larger than the sum of its proper divisors (1).

125344433 is an equidigital number, since it uses as much as digits as its factorization.

125344433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 17280, while the sum is 29.

The square root of 125344433 is about 11195.7328031710. The cubic root of 125344433 is about 500.4588228344.

Adding to 125344433 its reverse (334443521), we get a palindrome (459787954).

The spelling of 125344433 in words is "one hundred twenty-five million, three hundred forty-four thousand, four hundred thirty-three".