12535422014041 has 8 divisors (see below), whose sum is σ = 13044349280160. Its totient is φ = 12036376830912.

The previous prime is 12535422014039. The next prime is 12535422014057. The reversal of 12535422014041 is 14041022453521.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12535422014041 - 2¹ = 12535422014039 is a prime.

It is a super-2 number, since 2×12535422014041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12535422013988 and 12535422014006.

It is not an unprimeable number, because it can be changed into a prime (12535422414041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2470518160 + ... + 2470523233.

It is an arithmetic number, because the mean of its divisors is an integer number (1630543660020).

Almost surely, 2^{12535422014041} is an apocalyptic number.

It is an amenable number.

12535422014041 is a deficient number, since it is larger than the sum of its proper divisors (508927266119).

12535422014041 is an equidigital number, since it uses as much as digits as its factorization.

12535422014041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4941041495.

The product of its (nonzero) digits is 38400, while the sum is 34.

Adding to 12535422014041 its reverse (14041022453521), we get a palindrome (26576444467562).

The spelling of 12535422014041 in words is "twelve trillion, five hundred thirty-five billion, four hundred twenty-two million, fourteen thousand, forty-one".