Base | Representation |
---|---|
bin | 111010011000001010… |
… | …1001111001000000011 |
3 | 102222120220020000221211 |
4 | 1310300111033020003 |
5 | 4023221410044211 |
6 | 133331501230551 |
7 | 12025442164651 |
oct | 1646025171003 |
9 | 388526200854 |
10 | 125364924931 |
11 | 49192260684 |
12 | 20368562457 |
13 | ba8b82656c |
14 | 60d3a7bdd1 |
15 | 33dae92e21 |
hex | 1d3054f203 |
125364924931 has 2 divisors, whose sum is σ = 125364924932. Its totient is φ = 125364924930.
The previous prime is 125364924901. The next prime is 125364924943. The reversal of 125364924931 is 139429463521.
It is a strong prime.
It is an emirp because it is prime and its reverse (139429463521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 125364924931 - 231 = 123217441283 is a prime.
It is a super-2 number, since 2×1253649249312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (125364924901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62682462465 + 62682462466.
It is an arithmetic number, because the mean of its divisors is an integer number (62682462466).
Almost surely, 2125364924931 is an apocalyptic number.
125364924931 is a deficient number, since it is larger than the sum of its proper divisors (1).
125364924931 is an equidigital number, since it uses as much as digits as its factorization.
125364924931 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1399680, while the sum is 49.
The spelling of 125364924931 in words is "one hundred twenty-five billion, three hundred sixty-four million, nine hundred twenty-four thousand, nine hundred thirty-one".
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