Search a number
-
+
12538857194153 is a prime number
BaseRepresentation
bin1011011001110110111000…
…1000010000001010101001
31122101200222111221210121222
42312131232020100022221
53120414034420203103
642400134345511425
72432621366414243
oct266355610201251
948350874853558
1012538857194153
113aa4776aa93a4
1214a6145aa2575
136cc541c02524
14314c536cb093
1516b27004b638
hexb676e2102a9

12538857194153 has 2 divisors, whose sum is σ = 12538857194154. Its totient is φ = 12538857194152.

The previous prime is 12538857194147. The next prime is 12538857194173. The reversal of 12538857194153 is 35149175883521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8290299386944 + 4248557807209 = 2879288^2 + 2061203^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12538857194153 is a prime.

It is not a weakly prime, because it can be changed into another prime (12538857194173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6269428597076 + 6269428597077.

It is an arithmetic number, because the mean of its divisors is an integer number (6269428597077).

Almost surely, 212538857194153 is an apocalyptic number.

It is an amenable number.

12538857194153 is a deficient number, since it is larger than the sum of its proper divisors (1).

12538857194153 is an equidigital number, since it uses as much as digits as its factorization.

12538857194153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 36288000, while the sum is 62.

The spelling of 12538857194153 in words is "twelve trillion, five hundred thirty-eight billion, eight hundred fifty-seven million, one hundred ninety-four thousand, one hundred fifty-three".