Base | Representation |
---|---|
bin | 11100100000110100111110… |
… | …110010010010011001001001 |
3 | 121110000020110011220021211020 |
4 | 130200310332302102121021 |
5 | 112414033141124324431 |
6 | 1122412304443223053 |
7 | 35261636654421063 |
oct | 3440647662223111 |
9 | 543006404807736 |
10 | 125401213511241 |
11 | 36a583a0908018 |
12 | 12093718817a89 |
13 | 54c838c374555 |
14 | 22d7645c24733 |
15 | e76e90079696 |
hex | 720d3ec92649 |
125401213511241 has 16 divisors (see below), whose sum is σ = 171283736234688. Its totient is φ = 81559845849600.
The previous prime is 125401213511201. The next prime is 125401213511309. The reversal of 125401213511241 is 142115312104521.
It is a happy number.
It is not a de Polignac number, because 125401213511241 - 215 = 125401213478473 is a prime.
It is not an unprimeable number, because it can be changed into a prime (125401213511201) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6735715 + ... + 17209656.
It is an arithmetic number, because the mean of its divisors is an integer number (10705233514668).
Almost surely, 2125401213511241 is an apocalyptic number.
It is an amenable number.
125401213511241 is a deficient number, since it is larger than the sum of its proper divisors (45882522723447).
125401213511241 is a wasteful number, since it uses less digits than its factorization.
125401213511241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23987992.
The product of its (nonzero) digits is 9600, while the sum is 33.
Adding to 125401213511241 its reverse (142115312104521), we get a palindrome (267516525615762).
The spelling of 125401213511241 in words is "one hundred twenty-five trillion, four hundred one billion, two hundred thirteen million, five hundred eleven thousand, two hundred forty-one".
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