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12540405153 = 337369730559
BaseRepresentation
bin10111010110111011…
…10110010110100001
31012100221222120212010
423223131312112201
5201140320431103
65432212223133
7622522453653
oct135335662641
935327876763
1012540405153
115355806001
12251b90aaa9
13124b0c59a3
1486d6d06d3
154d5e1a903
hex2eb7765a1

12540405153 has 16 divisors (see below), whose sum is σ = 17177653760. Its totient is φ = 8131850496.

The previous prime is 12540405151. The next prime is 12540405167. The reversal of 12540405153 is 35150404521.

It is not a de Polignac number, because 12540405153 - 21 = 12540405151 is a prime.

It is a super-2 number, since 2×125404051532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12540405153.

It is not an unprimeable number, because it can be changed into a prime (12540405151) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 395088 + ... + 425646.

It is an arithmetic number, because the mean of its divisors is an integer number (1073603360).

Almost surely, 212540405153 is an apocalyptic number.

It is an amenable number.

12540405153 is a deficient number, since it is larger than the sum of its proper divisors (4637248607).

12540405153 is a wasteful number, since it uses less digits than its factorization.

12540405153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34296.

The product of its (nonzero) digits is 12000, while the sum is 30.

Adding to 12540405153 its reverse (35150404521), we get a palindrome (47690809674).

The spelling of 12540405153 in words is "twelve billion, five hundred forty million, four hundred five thousand, one hundred fifty-three".

Divisors: 1 3 37 111 3697 11091 30559 91677 136789 410367 1130683 3392049 112976623 338929869 4180135051 12540405153