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1254043401257 is a prime number
BaseRepresentation
bin10010001111111010110…
…011111011110000101001
311102212220102220100101102
4102033322303323300221
5131021240102320012
62400033302131145
7156413236014443
oct22177263736051
94385812810342
101254043401257
11443922897379
12183060720ab5
1391342c63b4a
14449a5c69493
152294952a2c2
hex123facfbc29

1254043401257 has 2 divisors, whose sum is σ = 1254043401258. Its totient is φ = 1254043401256.

The previous prime is 1254043401251. The next prime is 1254043401271. The reversal of 1254043401257 is 7521043404521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1028498194201 + 225545207056 = 1014149^2 + 474916^2 .

It is a cyclic number.

It is not a de Polignac number, because 1254043401257 - 220 = 1254042352681 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1254043401257.

It is not a weakly prime, because it can be changed into another prime (1254043401251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627021700628 + 627021700629.

It is an arithmetic number, because the mean of its divisors is an integer number (627021700629).

Almost surely, 21254043401257 is an apocalyptic number.

It is an amenable number.

1254043401257 is a deficient number, since it is larger than the sum of its proper divisors (1).

1254043401257 is an equidigital number, since it uses as much as digits as its factorization.

1254043401257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 134400, while the sum is 38.

Adding to 1254043401257 its reverse (7521043404521), we get a palindrome (8775086805778).

The spelling of 1254043401257 in words is "one trillion, two hundred fifty-four billion, forty-three million, four hundred one thousand, two hundred fifty-seven".