Base | Representation |
---|---|
bin | 10010010000000110101… |
… | …110100100000010100001 |
3 | 11102220102101002021022011 |
4 | 102100012232210002201 |
5 | 131022142242214334 |
6 | 2400105203112521 |
7 | 156421214213023 |
oct | 22200656440241 |
9 | 4386371067264 |
10 | 1254243319969 |
11 | 443a15724252 |
12 | 1830b7672741 |
13 | 913754c0143 |
14 | 449c462a013 |
15 | 2295bd6a564 |
hex | 12406ba40a1 |
1254243319969 has 2 divisors, whose sum is σ = 1254243319970. Its totient is φ = 1254243319968.
The previous prime is 1254243319919. The next prime is 1254243320081. The reversal of 1254243319969 is 9699133424521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1254205127569 + 38192400 = 1119913^2 + 6180^2 .
It is a cyclic number.
It is not a de Polignac number, because 1254243319969 - 227 = 1254109102241 is a prime.
It is a super-2 number, since 2×12542433199692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1254243319919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627121659984 + 627121659985.
It is an arithmetic number, because the mean of its divisors is an integer number (627121659985).
Almost surely, 21254243319969 is an apocalyptic number.
It is an amenable number.
1254243319969 is a deficient number, since it is larger than the sum of its proper divisors (1).
1254243319969 is an equidigital number, since it uses as much as digits as its factorization.
1254243319969 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12597120, while the sum is 58.
The spelling of 1254243319969 in words is "one trillion, two hundred fifty-four billion, two hundred forty-three million, three hundred nineteen thousand, nine hundred sixty-nine".
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