Base | Representation |
---|---|
bin | 10010010000000111011… |
… | …100010110101111100011 |
3 | 11102220110012200010220202 |
4 | 102100013130112233203 |
5 | 131022203330333011 |
6 | 2400110312255415 |
7 | 156421421230415 |
oct | 22200734265743 |
9 | 4386405603822 |
10 | 1254255324131 |
11 | 443a21483147 |
12 | 1830bb6a156b |
13 | 91377b33cb4 |
14 | 449c60729b5 |
15 | 2295ce3c23b |
hex | 12407716be3 |
1254255324131 has 2 divisors, whose sum is σ = 1254255324132. Its totient is φ = 1254255324130.
The previous prime is 1254255324103. The next prime is 1254255324149. The reversal of 1254255324131 is 1314235524521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1254255324131 - 210 = 1254255323107 is a prime.
It is a super-2 number, since 2×12542553241312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1254255324181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627127662065 + 627127662066.
It is an arithmetic number, because the mean of its divisors is an integer number (627127662066).
Almost surely, 21254255324131 is an apocalyptic number.
1254255324131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1254255324131 is an equidigital number, since it uses as much as digits as its factorization.
1254255324131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 144000, while the sum is 38.
The spelling of 1254255324131 in words is "one trillion, two hundred fifty-four billion, two hundred fifty-five million, three hundred twenty-four thousand, one hundred thirty-one".
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