Base | Representation |
---|---|
bin | 11100100001010000110100… |
… | …111100101101001011011111 |
3 | 121110010002121221111221201020 |
4 | 130201100310330231023133 |
5 | 112420030404442210221 |
6 | 1122434131414215223 |
7 | 35264045626061553 |
oct | 3441206474551337 |
9 | 543102557457636 |
10 | 125431113241311 |
11 | 36a6a044495839 |
12 | 12099482054513 |
13 | 54cb145a30017 |
14 | 22d8c80c0b863 |
15 | e77b3ee98ac6 |
hex | 721434f2d2df |
125431113241311 has 32 divisors (see below), whose sum is σ = 172417854866688. Its totient is φ = 81050401935360.
The previous prime is 125431113241297. The next prime is 125431113241321. The reversal of 125431113241311 is 113142311134521.
It is not a de Polignac number, because 125431113241311 - 29 = 125431113240799 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (125431113241321) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29530180 + ... + 33509606.
It is an arithmetic number, because the mean of its divisors is an integer number (5388057964584).
Almost surely, 2125431113241311 is an apocalyptic number.
125431113241311 is a deficient number, since it is larger than the sum of its proper divisors (46986741625377).
125431113241311 is a wasteful number, since it uses less digits than its factorization.
125431113241311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3980551.
The product of its digits is 8640, while the sum is 33.
Adding to 125431113241311 its reverse (113142311134521), we get a palindrome (238573424375832).
The spelling of 125431113241311 in words is "one hundred twenty-five trillion, four hundred thirty-one billion, one hundred thirteen million, two hundred forty-one thousand, three hundred eleven".
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