Base | Representation |
---|---|
bin | 10111010111010001… |
… | …11010000000000011 |
3 | 1012101011102211220002 |
4 | 23223220322000003 |
5 | 201142041204213 |
6 | 5432354310215 |
7 | 622556215331 |
oct | 135350720003 |
9 | 35334384802 |
10 | 12543303683 |
11 | 5357405789 |
12 | 252088836b |
13 | 124b89c0b1 |
14 | 86dc46b51 |
15 | 4d62de658 |
hex | 2eba3a003 |
12543303683 has 2 divisors, whose sum is σ = 12543303684. Its totient is φ = 12543303682.
The previous prime is 12543303599. The next prime is 12543303697. The reversal of 12543303683 is 38630334521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12543303683 - 214 = 12543287299 is a prime.
It is a super-2 number, since 2×125433036832 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12543302683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6271651841 + 6271651842.
It is an arithmetic number, because the mean of its divisors is an integer number (6271651842).
Almost surely, 212543303683 is an apocalyptic number.
12543303683 is a deficient number, since it is larger than the sum of its proper divisors (1).
12543303683 is an equidigital number, since it uses as much as digits as its factorization.
12543303683 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 38.
The spelling of 12543303683 in words is "twelve billion, five hundred forty-three million, three hundred three thousand, six hundred eighty-three".
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