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125442031000003 = 1000065712543379
BaseRepresentation
bin11100100001011010111111…
…101100101001100111000011
3121110011010210211012120002021
4130201122333230221213003
5112420220234414000003
61122443135023502311
735264613316355044
oct3441327754514703
9543133724176067
10125442031000003
1136a73737261503
121209b60a457997
1354cc1958c1073
1422d95d8bd08cb
15e7807d6e02bd
hex7216bfb299c3

125442031000003 has 4 divisors (see below), whose sum is σ = 125442053544040. Its totient is φ = 125442008455968.

The previous prime is 125442030999991. The next prime is 125442031000007. The reversal of 125442031000003 is 300000130244521.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 125442031000003 - 237 = 125304592046531 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (125442031000007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3728968 + ... + 16272346.

It is an arithmetic number, because the mean of its divisors is an integer number (31360513386010).

Almost surely, 2125442031000003 is an apocalyptic number.

125442031000003 is a deficient number, since it is larger than the sum of its proper divisors (22544037).

125442031000003 is a wasteful number, since it uses less digits than its factorization.

125442031000003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22544036.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 125442031000003 its reverse (300000130244521), we get a palindrome (425442161244524).

The spelling of 125442031000003 in words is "one hundred twenty-five trillion, four hundred forty-two billion, thirty-one million, three", and thus it is an aban number.

Divisors: 1 10000657 12543379 125442031000003