Base | Representation |
---|---|
bin | 10010010000011000000… |
… | …100111100100001100011 |
3 | 11102221011122210200011201 |
4 | 102100120010330201203 |
5 | 131023241301300344 |
6 | 2400154122022031 |
7 | 156431350312111 |
oct | 22203004744143 |
9 | 4387148720151 |
10 | 1254534400099 |
11 | 444054a66042 |
12 | 183179047917 |
13 | 913c08b6bc6 |
14 | 44a1115aab1 |
15 | 229776b64d4 |
hex | 1241813c863 |
1254534400099 has 4 divisors (see below), whose sum is σ = 1320562526440. Its totient is φ = 1188506273760.
The previous prime is 1254534400051. The next prime is 1254534400109. The reversal of 1254534400099 is 9900044354521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1254534400099 is a prime.
It is a super-2 number, since 2×12545344000992 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1254534400039) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33014063142 + ... + 33014063179.
It is an arithmetic number, because the mean of its divisors is an integer number (330140631610).
Almost surely, 21254534400099 is an apocalyptic number.
1254534400099 is a gapful number since it is divisible by the number (19) formed by its first and last digit.
1254534400099 is a deficient number, since it is larger than the sum of its proper divisors (66028126341).
1254534400099 is an equidigital number, since it uses as much as digits as its factorization.
1254534400099 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66028126340.
The product of its (nonzero) digits is 777600, while the sum is 46.
The spelling of 1254534400099 in words is "one trillion, two hundred fifty-four billion, five hundred thirty-four million, four hundred thousand, ninety-nine".
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