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125471000153 is a prime number
BaseRepresentation
bin111010011011010100…
…1111000011001011001
3102222212021211012210202
41310312221320121121
54023431034001103
6133350210551545
712031200622112
oct1646651703131
9388767735722
10125471000153
1149237121554
1220397b985b5
13baa77b6375
146103bb1209
1533e5447988
hex1d36a78659

125471000153 has 2 divisors, whose sum is σ = 125471000154. Its totient is φ = 125471000152.

The previous prime is 125471000147. The next prime is 125471000197. The reversal of 125471000153 is 351000174521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102914564809 + 22556435344 = 320803^2 + 150188^2 .

It is an emirp because it is prime and its reverse (351000174521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125471000153 - 226 = 125403891289 is a prime.

It is not a weakly prime, because it can be changed into another prime (125471000113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62735500076 + 62735500077.

It is an arithmetic number, because the mean of its divisors is an integer number (62735500077).

Almost surely, 2125471000153 is an apocalyptic number.

It is an amenable number.

125471000153 is a deficient number, since it is larger than the sum of its proper divisors (1).

125471000153 is an equidigital number, since it uses as much as digits as its factorization.

125471000153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4200, while the sum is 29.

Adding to 125471000153 its reverse (351000174521), we get a palindrome (476471174674).

The spelling of 125471000153 in words is "one hundred twenty-five billion, four hundred seventy-one million, one hundred fifty-three", and thus it is an aban number.