Base | Representation |
---|---|
bin | 111010011011110000… |
… | …1110110101011001001 |
3 | 102222220022102200101111 |
4 | 1310313201312223021 |
5 | 4023443313020121 |
6 | 133351453250321 |
7 | 12031436423422 |
oct | 1646741665311 |
9 | 388808380344 |
10 | 125485673161 |
11 | 49244433602 |
12 | 203a0a939a1 |
13 | baaa852c14 |
14 | 6105b10649 |
15 | 33e68952e1 |
hex | 1d37876ac9 |
125485673161 has 2 divisors, whose sum is σ = 125485673162. Its totient is φ = 125485673160.
The previous prime is 125485673099. The next prime is 125485673189. The reversal of 125485673161 is 161376584521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 77872251136 + 47613422025 = 279056^2 + 218205^2 .
It is an emirp because it is prime and its reverse (161376584521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 125485673161 - 217 = 125485542089 is a prime.
It is not a weakly prime, because it can be changed into another prime (125485673461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62742836580 + 62742836581.
It is an arithmetic number, because the mean of its divisors is an integer number (62742836581).
Almost surely, 2125485673161 is an apocalyptic number.
It is an amenable number.
125485673161 is a deficient number, since it is larger than the sum of its proper divisors (1).
125485673161 is an equidigital number, since it uses as much as digits as its factorization.
125485673161 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1209600, while the sum is 49.
The spelling of 125485673161 in words is "one hundred twenty-five billion, four hundred eighty-five million, six hundred seventy-three thousand, one hundred sixty-one".
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