Base | Representation |
---|---|
bin | 1011011010011101000110… |
… | …0111001110000110101011 |
3 | 1122102200110111001211211121 |
4 | 2312213101213032012223 |
5 | 3121101042221104042 |
6 | 42404552343440111 |
7 | 2433433540432414 |
oct | 266472147160653 |
9 | 48380414054747 |
10 | 12549116191147 |
11 | 3aa9060a31708 |
12 | 14a8129756037 |
13 | 7004b8462553 |
14 | 315547dcc80b |
15 | 16b670a19367 |
hex | b69d19ce1ab |
12549116191147 has 2 divisors, whose sum is σ = 12549116191148. Its totient is φ = 12549116191146.
The previous prime is 12549116191141. The next prime is 12549116191187. The reversal of 12549116191147 is 74119161194521.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12549116191147 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12549116191094 and 12549116191103.
It is not a weakly prime, because it can be changed into another prime (12549116191141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6274558095573 + 6274558095574.
It is an arithmetic number, because the mean of its divisors is an integer number (6274558095574).
Almost surely, 212549116191147 is an apocalyptic number.
12549116191147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12549116191147 is an equidigital number, since it uses as much as digits as its factorization.
12549116191147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 544320, while the sum is 52.
The spelling of 12549116191147 in words is "twelve trillion, five hundred forty-nine billion, one hundred sixteen million, one hundred ninety-one thousand, one hundred forty-seven".
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