Base | Representation |
---|---|
bin | 10010010000110101001… |
… | …110111000100001110011 |
3 | 11102222102202012210001121 |
4 | 102100311032320201303 |
5 | 131030242011410220 |
6 | 2400314434043111 |
7 | 156446440053643 |
oct | 22206516704163 |
9 | 4388382183047 |
10 | 1255023544435 |
11 | 444286088461 |
12 | 183294a19497 |
13 | 9146b03ab1b |
14 | 44a5a0c8523 |
15 | 229a55d7eaa |
hex | 124353b8873 |
1255023544435 has 16 divisors (see below), whose sum is σ = 1579640916096. Its totient is φ = 956098435968.
The previous prime is 1255023544429. The next prime is 1255023544469. The reversal of 1255023544435 is 5344453205521.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1255023544435 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1255023544391 and 1255023544400.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 72160572 + ... + 72177961.
It is an arithmetic number, because the mean of its divisors is an integer number (98727557256).
Almost surely, 21255023544435 is an apocalyptic number.
1255023544435 is a deficient number, since it is larger than the sum of its proper divisors (324617371661).
1255023544435 is a wasteful number, since it uses less digits than its factorization.
1255023544435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 144338622.
The product of its (nonzero) digits is 1440000, while the sum is 43.
Adding to 1255023544435 its reverse (5344453205521), we get a palindrome (6599476749956).
The spelling of 1255023544435 in words is "one trillion, two hundred fifty-five billion, twenty-three million, five hundred forty-four thousand, four hundred thirty-five".
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