Base | Representation |
---|---|
bin | 1011011010100111111101… |
… | …0010101110001101010011 |
3 | 1122102221222120000101010111 |
4 | 2312221333102232031103 |
5 | 3121123024143200303 |
6 | 42410153433542151 |
7 | 2433566002026154 |
oct | 266517722561523 |
9 | 48387876011114 |
10 | 12552030053203 |
11 | 3aaa316809373 |
12 | 14a8801574957 |
13 | 700861047994 |
14 | 315742db192b |
15 | 16b791745b6d |
hex | b6a7f4ae353 |
12552030053203 has 2 divisors, whose sum is σ = 12552030053204. Its totient is φ = 12552030053202.
The previous prime is 12552030053197. The next prime is 12552030053207. The reversal of 12552030053203 is 30235003025521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12552030053203 - 221 = 12552027956051 is a prime.
It is a super-2 number, since 2×125520300532032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12552030053207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6276015026601 + 6276015026602.
It is an arithmetic number, because the mean of its divisors is an integer number (6276015026602).
Almost surely, 212552030053203 is an apocalyptic number.
12552030053203 is a deficient number, since it is larger than the sum of its proper divisors (1).
12552030053203 is an equidigital number, since it uses as much as digits as its factorization.
12552030053203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27000, while the sum is 31.
Adding to 12552030053203 its reverse (30235003025521), we get a palindrome (42787033078724).
The spelling of 12552030053203 in words is "twelve trillion, five hundred fifty-two billion, thirty million, fifty-three thousand, two hundred three".
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