Base | Representation |
---|---|
bin | 10010010001000010111… |
… | …000011110010111011011 |
3 | 11110000000201010112012002 |
4 | 102101002320132113123 |
5 | 131031224123114011 |
6 | 2400353254311215 |
7 | 156455220431645 |
oct | 22210270362733 |
9 | 4400021115162 |
10 | 1255252551131 |
11 | 444393382597 |
12 | 18333965850b |
13 | 914a660cc47 |
14 | 44a7c69b895 |
15 | 229ba771c3b |
hex | 12442e1e5db |
1255252551131 has 2 divisors, whose sum is σ = 1255252551132. Its totient is φ = 1255252551130.
The previous prime is 1255252551073. The next prime is 1255252551173. The reversal of 1255252551131 is 1311552525521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1255252551131 - 210 = 1255252550107 is a prime.
It is a super-2 number, since 2×12552525511312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1255252551191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627626275565 + 627626275566.
It is an arithmetic number, because the mean of its divisors is an integer number (627626275566).
Almost surely, 21255252551131 is an apocalyptic number.
1255252551131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1255252551131 is an equidigital number, since it uses as much as digits as its factorization.
1255252551131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 75000, while the sum is 38.
The spelling of 1255252551131 in words is "one trillion, two hundred fifty-five billion, two hundred fifty-two million, five hundred fifty-one thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •