Base | Representation |
---|---|
bin | 11100100010110011001000… |
… | …001110010101111001011011 |
3 | 121110111012001220122000212220 |
4 | 130202303020032111321123 |
5 | 112423243041303033040 |
6 | 1122554425203035123 |
7 | 35304503355040032 |
oct | 3442631016257133 |
9 | 543435056560786 |
10 | 125536663330395 |
11 | 36aaa888796a19 |
12 | 120b5a1a66baa3 |
13 | 5508097340235 |
14 | 2300015003719 |
15 | e7a76b5992d0 |
hex | 722cc8395e5b |
125536663330395 has 16 divisors (see below), whose sum is σ = 200868449777952. Its totient is φ = 66949624293120.
The previous prime is 125536663330391. The next prime is 125536663330411. The reversal of 125536663330395 is 593033366635521.
125536663330395 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 125536663330395 - 22 = 125536663330391 is a prime.
It is not an unprimeable number, because it can be changed into a prime (125536663330391) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 203607952 + ... + 204223581.
It is an arithmetic number, because the mean of its divisors is an integer number (12554278111122).
Almost surely, 2125536663330395 is an apocalyptic number.
125536663330395 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
125536663330395 is a deficient number, since it is larger than the sum of its proper divisors (75331786447557).
125536663330395 is a wasteful number, since it uses less digits than its factorization.
125536663330395 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 407852062.
The product of its (nonzero) digits is 118098000, while the sum is 60.
The spelling of 125536663330395 in words is "one hundred twenty-five trillion, five hundred thirty-six billion, six hundred sixty-three million, three hundred thirty thousand, three hundred ninety-five".
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