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1255634113 = 11631079651
BaseRepresentation
bin100101011010111…
…0111010011000001
310020111200211012011
41022311313103001
510032420242423
6324332332521
743054466566
oct11265672301
93214624164
101255634113
11594855548
122b0614141
131701a3186
14bca9286d
1575379b0d
hex4ad774c1

1255634113 has 4 divisors (see below), whose sum is σ = 1256714928. Its totient is φ = 1254553300.

The previous prime is 1255634087. The next prime is 1255634117. The reversal of 1255634113 is 3114365521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1255634113 - 225 = 1222079681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1255634117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 538663 + ... + 540988.

It is an arithmetic number, because the mean of its divisors is an integer number (314178732).

Almost surely, 21255634113 is an apocalyptic number.

It is an amenable number.

1255634113 is a deficient number, since it is larger than the sum of its proper divisors (1080815).

1255634113 is a wasteful number, since it uses less digits than its factorization.

1255634113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1080814.

The product of its digits is 10800, while the sum is 31.

The square root of 1255634113 is about 35434.9278678538. The cubic root of 1255634113 is about 1078.8333632871.

Adding to 1255634113 its reverse (3114365521), we get a palindrome (4369999634).

The spelling of 1255634113 in words is "one billion, two hundred fifty-five million, six hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 1163 1079651 1255634113