12574110113 has 4 divisors (see below), whose sum is σ = 12574401840. Its totient is φ = 12573818388.

The previous prime is 12574110103. The next prime is 12574110119. The reversal of 12574110113 is 31101147521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31101147521 = 47 ⋅661726543.

It is a cyclic number.

It is not a de Polignac number, because 12574110113 - 2⁶ = 12574110049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12574110119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66995 + ... + 172152.

It is an arithmetic number, because the mean of its divisors is an integer number (3143600460).

Almost surely, 2^12574110113 is an apocalyptic number.

It is an amenable number.

12574110113 is a deficient number, since it is larger than the sum of its proper divisors (291727).

12574110113 is an equidigital number, since it uses as much as digits as its factorization.

12574110113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 291726.

The product of its (nonzero) digits is 840, while the sum is 26.

Adding to 12574110113 its reverse (31101147521), we get a palindrome (43675257634).

The spelling of 12574110113 in words is "twelve billion, five hundred seventy-four million, one hundred ten thousand, one hundred thirteen".