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1257501555113 = 2363353209561
BaseRepresentation
bin10010010011001000111…
…011101111100110101001
311110012211110000202122212
4102103020323233212221
5131100330344230423
62401404354254505
7156565026566606
oct22231073574651
94405743022585
101257501555113
11445337932571
12183866887435
139177453b52b
1444c132536ad
1522a9ce1d578
hex124c8eef9a9

1257501555113 has 4 divisors (see below), whose sum is σ = 1257554788308. Its totient is φ = 1257448321920.

The previous prime is 1257501555103. The next prime is 1257501555127. The reversal of 1257501555113 is 3115551057521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 487333836649 + 770167718464 = 698093^2 + 877592^2 .

It is a cyclic number.

It is not a de Polignac number, because 1257501555113 - 218 = 1257501292969 is a prime.

It is a super-2 number, since 2×12575015551132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1257501555103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26581148 + ... + 26628413.

It is an arithmetic number, because the mean of its divisors is an integer number (314388697077).

Almost surely, 21257501555113 is an apocalyptic number.

It is an amenable number.

1257501555113 is a deficient number, since it is larger than the sum of its proper divisors (53233195).

1257501555113 is an equidigital number, since it uses as much as digits as its factorization.

1257501555113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53233194.

The product of its (nonzero) digits is 131250, while the sum is 41.

The spelling of 1257501555113 in words is "one trillion, two hundred fifty-seven billion, five hundred one million, five hundred fifty-five thousand, one hundred thirteen".

Divisors: 1 23633 53209561 1257501555113