Base | Representation |
---|---|
bin | 10111011011010110… |
… | …10111100111001001 |
3 | 1012110112210101110222 |
4 | 23231223113213021 |
5 | 201224320104224 |
6 | 5440015315425 |
7 | 623453005652 |
oct | 135553274711 |
9 | 35415711428 |
10 | 12577503689 |
11 | 5374744753 |
12 | 253021bb75 |
13 | 12559b499a |
14 | 8745ca529 |
15 | 4d92e7b5e |
hex | 2edad79c9 |
12577503689 has 2 divisors, whose sum is σ = 12577503690. Its totient is φ = 12577503688.
The previous prime is 12577503623. The next prime is 12577503707. The reversal of 12577503689 is 98630577521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12519819664 + 57684025 = 111892^2 + 7595^2 .
It is a cyclic number.
It is not a de Polignac number, because 12577503689 - 220 = 12576455113 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12577503689.
It is not a weakly prime, because it can be changed into another prime (12577503089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6288751844 + 6288751845.
It is an arithmetic number, because the mean of its divisors is an integer number (6288751845).
Almost surely, 212577503689 is an apocalyptic number.
It is an amenable number.
12577503689 is a deficient number, since it is larger than the sum of its proper divisors (1).
12577503689 is an equidigital number, since it uses as much as digits as its factorization.
12577503689 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3175200, while the sum is 53.
The spelling of 12577503689 in words is "twelve billion, five hundred seventy-seven million, five hundred three thousand, six hundred eighty-nine".
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